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DAT Exam Questions & Answers 2026 (11–20)

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  1. Q11Compared to succession, evolution is generally <code>________</code>.

    • AFaster
    • BMore organized
    • CPermanent
    • DSimilar in rate
    • ESlower
    Show answer

    ✓ Correct answer: E. Slower

    While succession is a relatively fast process, evolution is a much slower one.<br/><br/><b>Key Takeaway: </b>In general, succession is a much faster process than evolution. While succession proceeds in a relatively ordered fashion, evolution is depended on random changes. Succession does proceed until a fixed point, whereas evolution is constantly taking place.

  2. Q12The cellular organelle that synthesizes proteins in prokaryotes is the

    • Aplasma membrane.
    • Bnucleus.
    • Cnucleoid.
    • Dribosome.
    • EGolgi apparatus.
    Show answer

    ✓ Correct answer: D. ribosome.

    Ribosomes produce proteins in both prokaryotes and eukaryotes.<br/><br/>Choice A is incorrect because prokaryotes do not have Golgi bodies—they lack membrane-bound organelles.<br/><br/>Choice B is incorrect because the nucleoid is not the site of protein synthesis in prokaryotes.<br/><br/>Choice C is incorrect because prokaryotes do not have nuclei.<br/><br/>Choice D is incorrect because the plasma membrane is not the site of protein synthesis in prokaryotes; the ribosome is.

  3. Q13Which of the following best accounts for the ability of legumes to grow well in nitrogen-poor soils?

    • AThese plants are capable of directly converting nitrogen gas into nitrates
    • BThese plants make their own proteins
    • CThese plants have a mutualistic relationship with nitrogen-fixing bacteria
    • DThese plants do not require nitrogen to make plant proteins
    • EThese plants can produce their own nitrogen from carbohydrates
    Show answer

    ✓ Correct answer: C. These plants have a mutualistic relationship with nitrogen-fixing bacteria

    Legume plants are able to live in nitrogen-poor soil because they obtain nitrogen from nitrogen-fixing bacteria. These plants cannot make their own proteins without nitrogen from nitrogen-fixing bacteria.

  4. Q14With which base is uracil complementary in RNA?

    • AG
    • BC
    • CU
    • DT
    • EA
    Show answer

    ✓ Correct answer: E. A

    Adenine (A) and uracil pair up in RNA.<br/><br/>Choices B and C are incorrect because C (cytosine) and G (guanine) pair up in DNA and RNA.<br/><br/>Choice D (T; thymine) is incorrect because T is found only in DNA and does not pair up with U.<br/><br/>Choice E is incorrect because U (uracil) is not complementary with itself.

  5. Q15Myriophyllum spicatum, or water milfoil, native to Eurasia, is an aggressive, invasive aquatic plant in North America. All of the following are reasons this species is successful as an invasive species EXCEPT

    • Amilfoil is a hardy plant capable of succeeding in harsher environments
    • Bmilfoil has few natural predators in a nonnative environment
    • Cmilfoil evolved from North American plant species
    • Dmilfoil is resistant to many native diseases that are adapted to native plant species
    • Emilfoil has few natural competitors among North American plant species
    Show answer

    ✓ Correct answer: C. milfoil evolved from North American plant species

    Because its evolutionary history is elsewhere, milfoil has adapted to an environment that lacks the natural predators and pathogens of North America, making it less susceptible to them and therefore more competitive than native plants in North America.

  6. Q16A panmictic population is one in which <code>________</code>.

    • Aall individuals are potential partners for breeding.
    • Ball individuals can survive
    • Call individuals are heterozygous
    • Dall individuals are homozygous
    • Eall individuals have an identical genotype.
    Show answer

    ✓ Correct answer: A. all individuals are potential partners for breeding.

    A panmictic population is one where all individuals are potential partners. This assumes that there are no mating restrictions, neither genetic nor behavioral, upon the population, and that therefore all recombination is possible. The Wahlund effect assumes that the overall population is panmictic.<br/><br/>A panmictic population is one where all individuals are potential partners. This assumes that there are no mating restrictions, neither genetic nor behavioral, upon the population, and that therefore all recombination is possible. The Wahlund effect assumes that the overall population is panmictic.<br/>In genetics, random mating involves the mating of individuals regardless of any physical, genetic, or social preference. In other words, the mating between two organisms is not influenced by any environmental, hereditary, or social interaction. Hence, potential mates have an equal chance of being selected. Random mating is a factor assumed in the Hardy-Weinberg principle and is distinct from lack of natural selection: in viability selection, for instance, selection occurs before mating.<br/><br/>In a panmictic species, all of the individuals of a single species are potential partners, and the species gives no mating restrictions throughout the population. Panmixia can also be referred to as random mating, referring to a population that randomly chooses their mate, rather than sorting between the adults of the population.<br/><br/>Panmixia allows for species to reach genetic diversity through gene flow more efficiently than monandry species. However, outside population factors, like drought and limited food sources, can affect the way any species will mate. When scientists examine species mating to understand their mating style, they look at factors like genetic markers, genetic differentiation, and gene pool.<br/><br/><img src="asset:assets/questions/a2ef9defaa4e2719.png"/>

  7. Q17Which of the following statements about sex-linked traits in humans is true?

    • AX-linked traits can only be inherited from the mother.
    • BThere are more sex-linked genes on the Y chromosome than on the X chromosome.
    • CY-linked traits are only inherited by females.
    • DY-linked traits can only be inherited from the father.
    • EThere is an equal probability of inheritance of the trait in children of both sexes.
    Show answer

    ✓ Correct answer: D. Y-linked traits can only be inherited from the father.

    The statement that is true about sex-linked traits is that Y-linked traits can only be inherited from the father. Since the father is the only parent with a copy of the Y-chromosome, only he can pass that trait on to offspring.<br/><br/><b>Key Takeaway: </b>Sex linkage is the phenotypic expression of an allele (i.e. trait) that is related to the chromosomal sex of an individual. Sex-linked traits are not equally inherited by the sexes, which is the opposite of autosomal traits. In humans, X-linked traits are more common, as the X-chromosome is bigger and has more genes. X-linked traits can be inherited from either parent and inherited by offspring of either sex, but Y-linked traits are only inherited from the father and can only be inherited by males.

  8. Q18Which of the following substances are produced by the light reactions of photosynthesis?

    • ANADPH and glucose
    • BATP and NADPH
    • CATP and NADH
    • DNADH and glucose
    • EATP and glucose
    Show answer

    ✓ Correct answer: B. ATP and NADPH

    The light reactions of photosynthesis convert solar energy to usable energy in the form of ATP (choices C and E are eliminated) and NADPH (a reduced electron carrier). The ATP and NADPH (i.e., energy) produced during these reactions are used later during the Calvin cycle to fix carbon dioxide into carbohydrates, like glucose. Because glucose is a product of the light-independent reactions, choice B could be eliminated. Remember that NADPH belongs with photosynthesis to eliminate choice D.

  9. Q19The location on an enzyme where a substrate binds is called the

    • Aactive site
    • Ballosteric site
    • Creaction center
    • Dbinding site
    • Elock-and-key model
    Show answer

    ✓ Correct answer: A. active site

    The other choices do not describe substrate binding sites on an enzyme.

  10. Q20In glycolysis, one <code>________</code> molecule is converted into two <code>________</code> molecules.

    • Aglucose; acetyl CoA
    • Bpyruvic acid; glucose
    • Cpyruvic acid; acetyl CoA
    • Dacetyl CoA; glucose
    • Eglucose; pyruvic acid
    Show answer

    ✓ Correct answer: E. glucose; pyruvic acid

    Glycolysis is the first step of respiration, converting a glucose molecule into two pyruvic acid molecules.<br/><br/>Choices A and B are incorrect because acetyl CoA is the molecule that enters the Krebs cycle during aerobic respiration.<br/><br/>Choice D is incorrect because pyruvic acid is the product, not the input, for glycolysis, and glucose is the input, not the product.<br/><br/>Choice E is incorrect because pyruvic acid is converted to acetyl CoA during the linking reaction between glycolysis and the Krebs cycle, though not in a 2:1 ratio.

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